Anelectron microscope uses electrons accelerated by a voltage of 50 kV.Determine the de Broglie wavelength associated with the electrons. Ifother factors (such as numerical aperture, etc.) are taken to beroughly the same, how does the resolving power of an electronmicroscope compare with that of an optical microscope which usesyellow light?
Anelectron microscope uses electrons accelerated by a voltage of 50 kV.Determine the de Broglie wavelength associated with the electrons. Ifother factors (such as numerical aperture, etc.) are taken to beroughly the same, how does the resolving power of an electronmicroscope compare with that of an optical microscope which usesyellow light?
Electronsare accelerated by a voltage, V= 50 kV = 50 × 103V
Chargeon an electron, e= 1.6 × 10−19C
Massof an electron, me= 9.11 × 10−31kg
Wavelengthof yellow light = 5.9 × 10−7m
Thekinetic energy of the electron is given as:
E= eV
=1.6 × 10−19× 50 × 103
=8 × 10−15J
De Brogliewavelength is given by the relation:
Thiswavelength is nearly 105 timesless than the wavelength of yellow light.
Theresolving power of a microscope is inversely proportional to thewavelength of light used. Thus, the resolving power of an electronmicroscope is nearly 105times that of an optical microscope.
Electronsare accelerated by a voltage, V= 50 kV = 50 × 103V
Chargeon an electron, e= 1.6 × 10−19C
Massof an electron, me= 9.11 × 10−31kg
Wavelengthof yellow light = 5.9 × 10−7m
Thekinetic energy of the electron is given as:
E= eV
=1.6 × 10−19× 50 × 103
=8 × 10−15J
De Brogliewavelength is given by the relation:
Thiswavelength is nearly 105 timesless than the wavelength of yellow light.
Theresolving power of a microscope is inversely proportional to thewavelength of light used. Thus, the resolving power of an electronmicroscope is nearly 105times that of an optical microscope.
