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Molar Mass

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Question

calculate the number of aluminium atoms present in 51g of aluminium oxide Al2o3

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Solution

The molecular mass of the Al₂ O₃ = 227 + 316= 92 g
As, 1 molecule of Al₂ O₃ has 2 atoms of aluminum in it.
So, 92 g of Al₂ O₃ has 26.023 10²³ aluminum atoms
In, 51 g of Al₂ O₃ there are (26.02310²³51)/92 aluminum atoms = 6.677 10²³ aluminum atoms

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