Question

Calculate the number of molecules in 0.02339g of chloroform.

Answer 1

Dear Student,

Molar mass of Chloroform CHCl₃ = 12+ 1+ 3(35.5) = 119.5g/mol

Note, Molar mass = 1 mole

1 mole contains = 6.022 × 10²³ molecules of CHCl₃

119.5 g chloroform contains = 6.022 × 10²³ molecules of CHCl₃

1g chloroform contains = 6.022 × 10²³ / 119.5 molecules of CHCl₃

0.02339 g chloroform contains = 6.022 × 10²³ × 0.02339 / 119.5 molecules of CHCl₃

= 0.1408/ 119.5 = 0.001178 × 10²³

= 1.178 × 10²⁰ molecules of CHCl₃

Hence, 0.02339 g chloroform contains 1.178 × 10²⁰ molecules of CHCl₃