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Question

factorise: m3-n3-m(m2-n2)+n(m-n)3

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Solution

m3-n3-m(m2-n2)+n(m-n)3(m-n)(m2+mn+n2)-m(m+n)(m-n)+n(m-n)3Taking (m-n) common(m-n)(m2+mn+n2)-m(m+n)+n(m2+n2-2mn)(m-n)m2+mn+n2-m2-n2+nm2+n3-2mn2(m-n)mn+nm2+n3-2mn2(m-n)n(m+m2+n2-2mn)

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