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Question

How many grams of Cu will get replaced in 2l of CuSO4 solution having molarity 1.50M, if it is made to react with 54g of Al?

(atomic mass of Cu=63.5g and Al=27g)

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Solution

The balanced equation for above mentioned reaction would be :
2 Al + 3 CuSO4 → Al2(SO4)3 + 3 Cu
2 moles of Aluminium displace 3 moles of Cu.

Molar Mass of Al is 27 g.
Number of moles in 54 g Al = 54 g / 27 g mol-1
​ = 2 moles.
Number of moles of Cu in given CuSO4 solution is : Molarity x volume of solution in L
= 1.5 mol L-1 x 2 L
= 3 moles.

It means the CuSO4 solution contains 3 moles Cu2+ ions which can be displaced by 2 moles of Al .
So amount of Cu deposited in gram = 3 mol x Molar mass of Cu
= 3 mol x 63.5 g mol-1
​ = 190. 5 g

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