How many grams of Cu will get replaced in 2l of CuSO4 solution having molarity 1.50M, if it is made to react with 54g of Al?
(atomic mass of Cu=63.5g and Al=27g)
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Solution
The balanced equation for above mentioned reaction would be :
2 Al + 3 CuSO4 → Al2(SO4)3 + 3 Cu
2 moles of Aluminium displace 3 moles of Cu.
Molar Mass of Al is 27 g.
Number of moles in 54 g Al = 54 g / 27 g mol-1
​ = 2 moles.
Number of moles of Cu in given CuSO4 solution is : Molarity x volume of solution in L
= 1.5 mol L-1 x 2 L
= 3 moles.
It means the CuSO4 solution contains 3 moles Cu2+ ions which can be displaced by 2 moles of Al .
So amount of Cu deposited in gram = 3 mol x Molar mass of Cu
= 3 mol x 63.5 g mol-1
​ = 190. 5 g