If 20.0g of CaCO3 is treated with 20.0g of HCL how many grams of CO2 will be produced ?
CaCO3 + 2 HCl → CaCl2 + CO2 + H2O
1 mole of CaCO3 reacts to form 1 mole of CO2
100g of CaCO3 reacts to form 44g of CO2
Therefore 20g of CaCO3 will form:
= 44*20/100
= 8.8g of CO2