If the area of a circle is 16pie r2 unit2- write the radius of the circle-

Given area of a circle is 16pie r2 nbsp;unit2 , nbsp;Let the radius of the circle is R , so using formula of area of circle nbsp; pi;R2 nbsp;= 16 n ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Physics

Measurement of Area

if the area o...

Question

if the area of a circle is 16pie r²unit², write the radius of the circle.

Open in App

Solution

Given area of a circle is 16pie r²unit^{2 ,
Let the radius of the circle is R , so using formula of area of circle}
$π$ R²= 16 $π$ r²
⇒ R²= 16 r²
⇒ R = $\sqrt{{16r}^{2}}$
We know that $\sqrt{16 r^{2}} = \sqrt{(4 * 4 * r * r)} = 4 \times r$
So radius = 4r

Suggest Corrections

Similar questions

If the sum of the areas of two circles with radii R₁ and R₂ is equal to the area of a circle of radius R, then

If the sum of the areas of two circles with radii $R_{1}$ and $R_{2}$ is equal to the area of a circle of radius R then

(a) $R_{1} + R_{2} = R$

(b) $R_{1} + R_{2} > R$

(d) $R_{1}^{2} + R_{2}^{2} = R^{2}$

Q. If the sum of the areas of two circles with radii R₁ and R₂ is equal to the area of a circle of radius R, then
(a)

R_{1} + R_{2} = R

(b)

R_{1} + R_{2} < R

(c)

R_{1}^{2} + R_{2}^{2} < R^{2}

(d)

R_{1}^{2} + R_{2}^{2} = R^{2}

Q. If the sum of the areas of two circles with radii

r_{1}

and

r_{2}

is equal to the area of circle of radius

r

, then
(a)

r = r_{1} + r_{2}

(b)

{r_{1}}^{2} + {r_{2}}^{2} = r^{2}

(c)

r_{1} + r_{2} < r

(d)

{r_{1}}^{2} + {r_{2}}^{2} < r^{2}

Join BYJU'S Learning Program

if the area of a circle is 16pie r2 unit2, write the radius of the circle.

Given area of a circle is 16pie r2 unit2 , Let the radius of the circle is R , so using formula of area of circle πR2 = 16 π r2⇒ R2 = 16 r2⇒ R = 16r2We know that 16 r2 = (4*4*r*r) = 4×rSo radius = 4r

if the area of a circle is 16pie r²unit², write the radius of the circle.

Given area of a circle is 16pie r²unit^{2 ,
Let the radius of the circle is R , so using formula of area of circle}
$π$ R²= 16 $π$ r²
⇒ R²= 16 r²
⇒ R = $\sqrt{{16r}^{2}}$
We know that $\sqrt{16 r^{2}} = \sqrt{(4 * 4 * r * r)} = 4 \times r$
So radius = 4r