$P (P - 1) - 20$ Find the value of $P$

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Solution

Given equation
$p (p - 1) - 20 = 0$
$p^{2} - p - 20 = 0$
$a = 1 b = - 1 c = - 20$
$\sqrt{b^{2} - 4 a c} = (1)^{2} - 4 (1) (- 20)$
$= 1 + 80$
$= \sqrt{81}$
$= 9$
$∴$ The roots are real and distinct.
$p^{2} - p - 20 = 0$
$p^{2} - 5 p + 4 p - 20 = 0$
$p (p - 5) + 4 (p - 5) = 0$
$(p + 4) (p - 5) = 0$
$p = 4 o r 5$

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