Question

P, Q, R and S are four men. P is the oldest but not the poorest. R is the richest but not the oldest. Q is older than S but not than P or R. P is richer than Q but not than S. The four men can be ordered (descending) in respect of age and richness, respectively, as

• A. PQRS, RPSQ
• B. PRQS, RSPQ
• C. PRQS, RSQP
• D. PRSQ, RSPQ

Answer 1

The correct option is B PRQS, RSPQ

The four men can he arranged in decending order in respect of age
P is the oldest . . . . . . (i)
Q > S . . . . . . (ii)
P < Q . . . . . . (iii)
R < Q . . . . . . (iv)
By law of combination of in equality we find the following descending sequence
P > R > Q > S
Now, the descending order in respect of richness
R > P > Q . . . . . . . . (i)
S < P . . . . . . . . (ii)
R is the richest ..... (iii)
So, from law of combination of inequality we get
R > S > P > Q