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Question

P,Q,R and S are four points with the position vectors, 3i4j+5k,4k,4i+5j+k and 3i+4j+3k respectively. Then the line PQ meets the line RS at the point


  1. 3i+4j+3k

  2. i+4j+k

  3. i+j+k

  4. 3i+4j+3k


Solution

The correct option is A

3i+4j+3k


Equation of PQ:x3=y4=z41a point A on PQ=(3λ,4λ,λ+4)Equation of RSx+41=y51=z12=ma point on RS, B=(m4,m+5,2m+1)to intersect A = Bλ=1,m=1Point is (3,4,3)

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