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Question

P,Q,R,S,T are points on a circle with centre O so that PTQ= 2 x RTS and PQ %undefined RS. Find SOQ, if P,O,Q are in a straight line
  1. 45o
  2. 90 o
  3. 60 o
  4. 30 o


Solution

The correct option is A 45o

PTQ= 90 (angle in a semi circle)

, hence RTS = 45.

ROS = 90 ( Inscribed angle= 2 *Angle at circumference)

OR=OS=OR (radius)

RSO = SOQ= 45 (interior alternate angles)

Option (a)

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