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Question

PT diagram of one mole of an ideal monatomic gas is shown. Process AB and CD are adiabatic. Work done in the complete cycle is


A
2.5RT
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B
2RT
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C
1.5RT
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D
3.5RT
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Solution

The correct option is A 2.5RT

From the figure, AB and CD are adiabatic QAB=QCD=0
BC and AD are isobaric, 
QBC=nCPΔT=1×5R2×(4TT)=7.5RT
QAD=nCPΔT=1×5R2×(3T5T)=5RT
Hence, Qnet=QBC+QAD=2.5RT
From the figure, it is evident that it is a cyclic process
In a cyclic process, Qnet=Wnet
Wnet=2.5RT

Physics

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