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P(t1) and P(t2) are the points t1and t2 on the parabola }y^2=4ax . The normals at }P and }Q meet on } the parabola. Show that the middle point of }PQ lies on the }{ parabola }y^2=2a(x+2a) .

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Solution

99996110332-0-099996110332-0-1

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