the total no. of valence electrons in 4.2g of N3- ion is ??in terms of Na(Na is the avogadro no._)

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Solution

Number of moles of nitride ions in 4.2 g = 4.2/14
= 0.3 moles
Therefore, number of nitride ions in 0.3 moles = 0.3 x N_a
Number of valence electrons in one nitride ion = 8
So, number of valence electrons in 0.3 x N_a nitride ions = 8 x 0.3 x N_a
= 2.4 x N_a

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