What is Kc for the reactionFe3-aq- - 3OH-aq- Fe-OH-3 -s-

Fe3+(aq) + 3OH (aq) nbsp; #8660; Fe(OH)3 (s) Equilibrium nbsp;constant, nbsp;Kc=1[Fe3+][OH ]3 Fe(OH)3 nbsp; doesnot appear in the equilibrium law be ...

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Standard VII

Physics

Measurement of Volume

what is Kc fo...

Question

what is K_c for the reaction
Fe³⁺(aq) + 3OH^-(aq) Fe(OH)₃(s)

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Solution

Fe³⁺(aq) + 3OH^-(aq) $\Leftrightarrow$ Fe(OH)₃(s)
$Equilibrium constant, K_{c} = \frac{1}{[F e^{3 +}] [O H^{-}]^{3}}$
Fe(OH)₃doesnot appear in the equilibrium law because it is a solid.

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Similar questions

Q. The expression for equilibrium constant,

K_{c}

for the following reaction is :

F e_{(}^{3 +} a q) + 3 O H_{(}^{-} a q) ⇌ F e (O H)_{3 (s)}

In the following reaction,

F e (O H)_{3} (s) ⇋ F e^{3 +} (a q) + 3 O H^{-} (a q)

What is the solubility product expression for the saturated solution when the ionic solid

F e (O H)_{3}

is added to water and dissociates into its component ions?

Q. Write the expression for the equlibrium constant,

K_{c}

for each of the following reactions.
(i)

2 N O C l (g) \to 2 N O (g) + C l_{2} (g)

(ii)

2 C u (N O_{3})_{2} (s) \to 2 C u O (s) + 4 N O_{2} (g) + O_{2} (g)

(iii)

C H_{3} C O O C_{2} H_{5} (a q) + H_{2} O (l) \to C H_{3} C O O H (a q) + C_{2} H_{5} O H (a q)

(iv)

F e^{3 +} (a q) + 3 O H^{-} (a q) \to F e (O H)_{3} (s)

(v)

I_{2 (s)} + 5 F_{2} (g) \to 2 I F_{5} (g)

Q. Write the expression for the equilibrium constant,

K_{c}

for each of the following reactions.
(i)

2 N O C l (g) ⇌ 2 N O (g) + {C l}_{2} (g)

(ii)

{2 C u ({N O}_{3})}_{2} (s) ⇌ 2 C u O (s) + 4 {N O}_{2} (g) + O_{2} (g)

(iii)

{C H}_{3} {C O O C}_{2} H_{5} (a q) + H_{2} O (1) ⇌ {C H}_{3} C O O H (a q) + C_{2} H_{5} O H (a q)

(iv)

{F e}^{3 +} (a q) + 3 {O H}^{-} (a q) ⇌ {F e (O H)}_{3} (s)

(v)

I_{2} (s) + 5 F_{2} ⇌ 2 I F_{5}

Q. If the concentration of

{O H}^{-}

ions in the reaction:

F e {(O H)}_{3} (s) ⇌ {F e}^{3 +} (a q) + 3 {O H}^{-} (a q .)

is decreased by

1 / 4

times, then equilibrium concentration of

{F e}^{3 +}

will increase by:

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what is Kc for the reactionFe3+(aq) + 3OH-(aq) Fe(OH)3 (s)

Fe3+(aq) + 3OH-(aq) ⇔ Fe(OH)3 (s) Equilibrium constant, Kc=1[Fe3+][OH-]3 Fe(OH)3 doesnot appear in the equilibrium law because it is a solid.

what is K_c for the reaction
Fe³⁺(aq) + 3OH^-(aq) Fe(OH)₃(s)

Fe³⁺(aq) + 3OH^-(aq) $\Leftrightarrow$ Fe(OH)₃(s)
$Equilibrium constant, K_{c} = \frac{1}{[F e^{3 +}] [O H^{-}]^{3}}$
Fe(OH)₃doesnot appear in the equilibrium law because it is a solid.