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Question

When a ball falls from rest under gravity, then the distance travelled by it in last two seconds is six times the distance travelled by it in first two seconds. The total time of journey is ?

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Solution

let t is the total time journey.Distance travelled in first two seconds is S1 s1 = ut + 12at2s1 = 0 + 0.5×10×4since t= 2 ss1 = 20 mDistance travelled in t secondss = ut + 12at2s = 5t2distance travelled in (t-2) secondss2 = 0.5×10(t-2)2distance travelled in last two seconds x = s-s2x = 5t2 - 0.5×10(t-2)2x = 4t-4x = 6s14t-4 = 6(20)4t-4 = 120t = 31 s

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