Question

Part of a simple harmonic motion is graphed in the figure, where y is the displacement from the mean position.The correct equation describing this SHM is

• A. y=4 cos (0.6t)
• B. $y=2sin(\frac{10}{3}t-\frac{\pi }{2})$
• C. $y=4sin(\frac{10}{3}t+\frac{\pi }{2})$
• D. $y=2cos(\frac{10}{3}t+\frac{\pi }{2})$

Answer 1

The correct option is B $y=2sin(\frac{10}{3}t-\frac{\pi }{2})$

From the graph , at $t=0$ ,$y=-2$
so. If $y=2\sin (\frac{10}{3}t-\frac{\pi }{2})$, then at $t=0,y=2\sin (0-\frac{\pi }{2})=-2$
$\therefore$ Ans : (B)