Question

$PC{l}_5$ and $PB{r}_5$ exist in $s{p}^{3}d$ hybrid state in gaseous phase but in solid state, which of the following statement is true?

• A. $P$ in $PC{l}_5$ exists in $s{p}^3$-hybridization state, while $P$ in $PB{r}_5$ exists in $s{p}^3{d}^2$ and $s{p}^3$-hybridization states
• B. $P$ in $PC{l}_5$ and $PB{r}_5$ exists in $s{p}^3{d}^2$ and $s{p}^3$- hybridization state
• C. $P$ in $PC{l}_5$ exists in $s{p}^3{d}^2$ and $s{p}^3$-hybridization states, while $P$ in $PB{r}_5$ exists in $s{p}^3$-hybridization state
• D. $P$ in $PC{l}_5$ and $PB{r}_5$ exists in $s{p}^3$-hybridization state

Answer 1

Answer: (C)

$P$ in $PC{l}_5$ exists in $s{p}^3{d}^2$ and $s{p}^3$-hybridization states, while $P$ in $PB{r}_5$ exists in $s{p}^3$-hybridization state

In the solid state, $PC{l}_5$ exists in the form of $\left[PC{l}_4{]}^{+}\right[PC{l}_6{]}^{-}$ in which the $P$ atom has $s{p}^3$ and $s{p}^3{d}^2$ hybridization.
In $PB{r}_5$, the $P$ atom exists in $s{p}^3$ hybridization.
Thus, the statement C is true.