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Question

Percent by mass of a solute (molar mass = 28 g) in its aqueous solution is 28. Calculate the mole fraction (X) and molality (m) of the solute in the solution.


  1. X = 0.2, m = 1259

  2. X = 0.8, m = 1259

  3. X = 0.2, m = 10

  4. X = 0.8, m = 10


Solution

The correct option is A

X = 0.2, m = 1259


Mol. of solute in 100 g solution =2828=1
Mol. of water in 100 g solution =1002818=4
Mol. fraction of solute =11+4=0.2;
Molality =1×100072=1259

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