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Question

Percentage of C, H and N are given as follows C=40%, H=13.33%, N=46.67%. The empirical formula will be:

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Solution

Given percentages are
C40 %
H13.33 %
N46.67 %
Percentages of elementsAtomic weight of elementC=4012=3.33(1)
H=13.331=13.33(2)
N=46.6714=3.33(3)
Simple ratio of C,H and N obtained by 1,2 and 3 is
C:H:N=3.33:13.33:3.33
=1:4:1
For one molecule, C has 1 atom
H has 4 atoms
N has 1 atom.
So, the Empirical formula is CH4N .

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