Perimeter of a rectangle is 44 cm. If its length is 9 cm, then its breadth is

13 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

12 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
13 cm

We know that if ' $l$ ' is the length of the rectangle and ' $b$ ' is its breadth, then its perimeter is given by

$P = l + b + l + b = (2 \times l) + (2 \times b)$

Given $P = 44 cm$ and $l = 9 cm$

Then,

$P = (2 \times l) + (2 \times b)$

$⟹ b = \frac{P - (2 \times l)}{2}$

i.e., $b = \frac{44 - (2 \times 9)}{2} = 13 cm$

Suggest Corrections

Similar questions

Q. A rectangle is having an area of 88

{cm}^{2}

and its breadth is 8 cm. Find its length.

Q. If the area of a square is

121 c m^{2}

, then its perimeter will be

The length of each side of a rhombus is 10 cm and one if its diagonals is of length 16 cm. The length of the other diagonal is
(a) 13 cm
(b) 12 cm
(c) $\frac{23}{9}$ cm
(d) 6 cm

A rectangle is having an area of 88 cm^{2} and its breadth is 8cm. What will be the length?

The area of a rhombus is 54 cm². If length of one of its diagonals is 9 cm, then what is the length of the other diagonal?

Perimeter of a rectangle is 44 cm. If its length is 9 cm, then its breadth is

The correct option is A 13 cm We know that if 'l' is the length of the rectangle and 'b' is its breadth, then its perimeter is given by P=l+b+l+b=(2×l)+(2×b) Given P=44 cm and l=9 cm Then, P=(2×l)+(2×b) ⟹b=P−(2×l)2 i.e., b=44−(2×9)2= 13cm