CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

pH of a saturated solution of  Ca(OH)2 is 9. The solubility product (Ksp) of  Ca(OH)2 is:


A
0.5×1015 
loader
B
 0.25×1010 
 
loader
C
0.125×1015  
loader
D
0.5×1010 
loader

Solution

The correct option is A 0.5×1015 
 Ca(OH)2    Ca2+ +  2OH
pH = 9,   Hence pOH = 14 – 9 = 5
               [OH]=  105M

Hence  [Ca2+]= 1052
Thus Ksp =  [Ca]2+ +  [OH]2
             = ( 1052) ( 105)2
            = 0.5×1015

Chemistry

Suggest Corrections
thumbs-up
 
2


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image