Question

Phosphorous pentachloride in gaseous phase exists as a monomer. In solid state, it exists as $PC{l}_4^{+}$ ions. The hybrid state of P-atom in $PC{l}_5$ is $s{p}^{3}d$ The hybrid states of P - atoms in $PC{l}_4^{+}$ and $PC{l}_6^{-}$ will be:

• A. $s{p}^{3}d,s{p}^3{d}^2$
• B. $s{p}^3,s{p}^3{d}^2$
• C. $s{p}^3{d}^2,s{p}^{3}d$
• D. $s{p}^3,s{p}^{3}d$

Answer 1

The correct option is B $s{p}^3,s{p}^3{d}^2$

Steric number =$\frac{M+V-C+A}{2}$
M=Number of monovalent surrounding atom
V= Number of valence electron on central atom
C= magnitude of charge on cation
A=magnitude of charge on anion
$PC{l}_4^{+}$
$H=\frac{4+5-1+0}{2}$
$H=\frac{8}{2}=4$
hybridisation= $s{p}^3$

$PC{l}_6^{-}$
$H=\frac{6+5-1+0}{2}$
$H=\frac{10}{2}=5$
hybridisation= $s{p}^3{d}^2$