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Question

Photoelectric work function of a metal 1 eV. If a light of wavelength 500 Å falls on the metal, the speed of the photoelectron emitted approximately will be- (h = 6.625 × 1034 J s)


  1. 11000× velocity of light

  2. 110× velocity of light
     

  3. Equal to velocity of light


     

  4. 1100× velocity of light
     


Solution

The correct option is D

1100× velocity of light
 


hv=w+KE=w+12mev2or     hcλ=1+12mev2or     6.625×1034×3×108500×1010=1.6×1019+12×9.1×1031×v2or     12×9.1×1031×v2=6.625×35×10181.6×1019=38.15×1019or     v2=38.15×2×10129.1or     v2=8.385×1012or     v=2.889×106m/svc3×1063×108=1100

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