Identify the compound which on reacting with sulphuric acid produces a gas that turns lime water milky.

C a S O_{4} + H C l \to

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C H_{3} C O O H + H C l \to

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N a H C O_{3} + H C l \to

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N a O H + H C l \to

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Solution

The correct option is C $N a H C O_{3} + H C l \to$
$M e t a l h y d r o g e n c a r b o n a t e / c a r b o n a t e + A c i d \to S a l t + C a r b o n d i o x i d e + W a t e r$
$C u C O_{3} (s) + H_{2} S O_{4} (a q) \to C u S O_{4} (a q) + C O_{2} (g) + H_{2} O (l)$
$N a H C O_{3} (s) + H C l (a q) \to N a C l (a q) + H_{2} O (l) + C O_{2} (g)$
The carbon dioxide gas released from the above reactions turns the lime water milky.

Reaction between sodium hydroxide and sulphuric acid:
$N a O H (a q) + H_{2} S O_{4} (a q) \to N a_{2} S O_{4} (a q) + H_{2} O (l)$

$C H_{3} C O O H$ is a weak acid while $C a S O_{4}$ is a salt.

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