Question

Two workers P and Q working together completed a job in 10 days. If P worked four times as efficiently as he actually did and Q worked 23rd as efficiently as he actually did, the work would have been completed in 3 days. P alone could complete the work in:

10 days

7.5 days

6.25 days

15 days

12.5 days

Solution

The correct option is **E**

12.5 days

Let P’s 1 day’s work = ‘x’ and Q’s 1 day’s work = ‘y’

Then, x+y=110 and 4x+23y=13

Solving, we get - x = 225 and y = 150

∴ P’s 1 day’s work = 225

So, P alone could complete the work in 252=1212 days

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