Pick up the coloured anion from the options given below.

$S O_{3}^{-}$

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$M N O_{4}^{-}$

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$C l^{-}$

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$C O_{3}^{-}$

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Solution

The correct option is B
$M N O_{4}^{-}$

Manganate ion has a deep purple colour and is used as an indicator for many reactions. So, $M N O_{4}^{-}$ is the correct option.

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