Pick up the major product in the following elimination reaction:

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Both will be formed in equal amounts

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Third product having rearranged skeleton will be formed.

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Solution

The correct option is A

Thus, here, Saytzeff product (having more alkyl groups on the doubly bonded carbon atoms) is not stable because of steric repulsion between bulky methyl groups.

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The product formed in the following reaction will be:

$2 K H C O_{3} + H_{2} S O_{4} \to$

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