Question

# Pipe A can fill a tank in 12 hours and pipe B can fill it in 15 hours seperately. A third pipe C can empty in 20 hours, Intially pipe A was opened, after one hour pipe B was opened and then after 1 hour when pipe B, was opened pipe C was also opened. In how many total hours the tank will be full?

A
923 hours
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B
623 hours
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C
10 hours
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D
none of these
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Solution

## The correct option is A 923 hours Efficiency of pipe A = 8.33% Efficiency of pipe B = 6.67% Efficiency of pipe C = 5% When tap C was opened,pipe A had filled 16.66% capacity When tap C was opened,pipe B had filled 6.67% capacity Therefore rest capacity of the tank to be filled = 100 - 23.34 = 76.66% Now, the net efficiency of A, B and C = 10% Hence, pipes A, B and C will take = 76.6610 = 7.66 = 723 Total time = 2hours + 723 hours = 923 hours.

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