Please explain this statement additive inverse of an integer 8 is (-8)and Additive inverse of (-8) is 8.

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Solution

Suppose our number is x.
Then the additive inverse of x is a number y such that x+ y = 0
So additive inverse of 8 is( -8) becasue 8 +(-8) = 0
and additive inverse of (-8) is 8 again because (-8)+8 = 0

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Is this statement true or false . For subtraction , we add the Additive inverse of the integer that is being subtracted , to the other integer. Please explain in detail.

The additive inverse of an integer x is given by -x.

Therefore, the additive inverse of -10 is -(-10) = 10

Q. Write additive inverse of

\frac{2}{8} a n d \frac{- 6}{- 5}

What will be the integer which is 8 more than its additive inverse?

Q. Which of the following statements are true:

(i) −13 > −8 − (−2)
(ii) −4 + (−2) < 2.
(iii) The negative of a negative integer is positive.
(iv) If a and b are two integers such that a > b, then a − b is always positive integer,
(v) The difference of two integers is an integer.
(vi) Additive inverse of a negative integer is negative.
(vii) Additive inverse of a positive integer is negative.
(viii) Additive inverse of a negative is positive.

Please explain this statement additive inverse of an integer 8 is (-8)and Additive inverse of (-8) is 8.

Suppose our number is x. Then the additive inverse of x is a number y such that x+ y = 0 So additive inverse of 8 is( -8) becasue 8 +(-8) = 0 and additive inverse of (-8) is 8 again because (-8)+8 = 0

Suppose our number is x.
Then the additive inverse of x is a number y such that x+ y = 0
So additive inverse of 8 is( -8) becasue 8 +(-8) = 0
and additive inverse of (-8) is 8 again because (-8)+8 = 0