Please follow the Aufbau principle, Pauli exclusion principle and Hund's rule to determine the four quantum numbers (principle, angular, magnetic, spin) for the final electron of Helium.

0, 0, 0, + 1 / 2

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1, 1, 0, - 1 / 2

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1, 0, 1, - 1 / 2

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1, 0, 0, - 1 / 2

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Solution

The correct option is D $1, 0, 0, - 1 / 2$
The electronic configuration of Helium is $1 s^{2}$ . Thus last electron is in $1 s$ . Hence value of $n = 1, l = 0, m = 0, s = \pm \frac{1}{2}$ . Thus correct set from given options is $1, 0, 0, - \frac{1}{2}$ i.e., option D

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Please follow the Aufbau principle, Pauli exclusion principle and Hund's rule to determine the four quantum numbers (principle, angular, magnetic, spin) for the final electron of Helium.

The correct option is D 1,0,0,−1/2The electronic configuration of Helium is 1s2. Thus last electron is in 1s. Hence value of n=1,l=0,m=0,s=±12. Thus correct set from given options is 1,0,0,−12 i.e., option D

The correct option is D $1, 0, 0, - 1 / 2$
The electronic configuration of Helium is $1 s^{2}$ . Thus last electron is in $1 s$ . Hence value of $n = 1, l = 0, m = 0, s = \pm \frac{1}{2}$ . Thus correct set from given options is $1, 0, 0, - \frac{1}{2}$ i.e., option D