CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

I vs V - Varying Intensity

Plot a graph ...

Question

Plot a graph to show the variation of stopping potential with frequency of incident radiation in relation to photoelectric effect.

Open in App

Solution

$h f - ϕ = e V$
where, $h =$ Plantis constant
$f =$ Frequency of incident radiation
$ϕ =$ Work function
$V =$ Stopping potential
$e =$ Electric charge

$\frac{n f}{e} - \frac{ϕ}{e} = V \to$ Straight line equation

Suggest Corrections

thumbs-up

0

Similar questions

Q. What is stopping voltage (or cut voltage)? Plot a graph of variation of photoelectric current with collector plate potential for two incident radiations of same frequency and different intensities.

Q. Draw a graph showing the variation of stopping potential

(V_{0})

3

frequency of incident radiation

(v)

in relation to the electric effect.
How can the value of Plancks constant be determined from this graph?

Q. The stopping potential as function of frequency of incident radiation is plotted for two different photoelectric surfaces A and B. The graphs show that the work function of A is

Q. Following graphs show the variation of stopping potential corresponding to the frequency of incident radiation (F) for a given metal. The correct variation is shown in graph (

v_{0}

= Threshold frequency) :

Q. Draw a plot showing the variation of photoelectric current with collector plate potential foe two different frequencies,

v_{1} > v_{2}

, of incident radiation having the same intensity. In which case will the stopping potential be higher ? Justify your answer.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

I vs V - Varying Intensity

PHYSICS

Watch in App

explore_more_icon

Explore more

I vs V - Varying Intensity

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon