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Question

PN is the ordinate of any point P on the hyperbola x2a2y2b2=1. If Q divides AP in the ratio a2:b2 then NQ is

A
perpendicular to A’P
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B
parallel to A’P
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C
perpendicular to OP
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D
none
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Solution

The correct option is A perpendicular to A’P
A=(a,0);A=(a,0);P(a sec θ,b tan θ) and N=(asec θ,0); the point Q which divides AP in the ratio
a2:b2 is Q=(a3 secθ+ab2a2+b2,ab2tanθa2+b2)
the product of slope of NQ and slope of A’P is - 1.

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