PN is the ordinate of any point P on the hyperbola x2a2−y2b2=1. If Q divides AP in the ratio a2:b2then NQ is
A
perpendicular to A’P
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B
parallel to A’P
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C
perpendicular to OP
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D
none
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Solution
The correct option is Aperpendicular to A’P A=(a,0);A′=(−a,0);P(asecθ,btanθ)andN=(asecθ,0); the point Q which divides AP in the ratio a2:b2 is Q=(a3secθ+ab2a2+b2,ab2tanθa2+b2) ∴ the product of slope of NQ and slope of A’P is - 1.