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Question

Polarising action of $$Cd^{2+}$$  on anion is stronger than that of $$Ca^{2+}$$ because:


A
The charges of the ions are same
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B
Their radii are same (Ca2+=0.104nm;Cd2+=0.099nm)
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C
The Ca2+ ion has a noble-gas electron configuration, and the Cd2+ ion, an 18 electron configuration of its outer shell
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D
All of the above are correct
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Solution

The correct option is C The $$Ca^{2+}$$ ion has a noble-gas electron configuration, and the $$Cd^{2+}$$ ion, an 18 electron configuration of its outer shell
Polarising action of $$Cd^{2+}$$  on anion is stronger than that of $$Ca^{2+}$$ because the $$Ca^{2+}$$ ion has a noble-gas electron configuration, and the $$Cd^{2+}$$ ion, an 18 electron configuration of its outer shell. A cation with 18 valence electrons has more polarizing power than a cation with 8 valence electrons.

Chemistry

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