Question

Polarization of electrons in acrolein may be written as:

• A. $\stackrel{\delta -}{C{H}_2}=CH-CH=\stackrel{\delta +}{O}$
• B. $\stackrel{\delta +}{C{H}_2}=\stackrel{\delta -}{CH}-CH=O$
• C. $\stackrel{\delta +}{C{H}_2}-CH=CH-\stackrel{\delta -}{O}$
• D. $\stackrel{\delta -}{C{H}_2}-CH=\stackrel{\delta +}{CH}=O$

Answer 1

The correct option is C $\stackrel{\delta +}{C{H}_2}-CH=CH-\stackrel{\delta -}{O}$

In $C{H}_2=CH-CHO$ due to $-M$ effect of $-CHO$ group polarization of electron tekes place as fallows:

Hence molecule bearing formal charge can be represented as: $\stackrel{\delta +}{C{H}_2}-CH=CH-\stackrel{\delta -}{O}$