Question

# Potassium chlorate decomposes, on heating, to form potassium chloride and oxygen. When 24.5 g of potassium chlorate is decomposed completely, then 14.9 g of potassium chloride is formed. Calculate the mass of oxygen formed. Which law of chemical combination have you used in solving this problem?

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Solution

## Chemical reaction: $\begin{array}{ccccc}2{\mathrm{KClO}}_{3}& \to & 2\mathrm{KCl}& +& 3{\mathrm{O}}_{2}\\ 24.5\mathrm{g}& & 14.9\mathrm{g}& & \end{array}$ So, mass of oxygen formed during the reaction: Mass of reactants = 24.5 g Mass of products = mass of the potassium chloride + mass of oxygen 24.5 = 14.9 + mass of oxygen Mass of oxygen = 24.5 – 14.9 = 9.6 g We have used the law of conservation of mass, proposed by Antoine Lavoisier, to solve this problem.

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