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Question

Potential energy of a particle moving along xaxis is given by:
U=(x334x+6)
Here, U is in joule and x is in metre.
Find the position of stable equilibrium.

A
X=2
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B
X=2
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C
X=1
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D
X=1
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Solution

The correct option is A X=2
U=X334x+6
F=dUdx=X2+4
F=0 at X=±2m
For X>2m,F=ve
i.e.,displacement is in positive direction and force is negative. Therefore X=2 is stable equilibrium position.
For X<2m,F=ve
i.e.,force and displacement are in negative directions. Therefore X=2 is unstable equilibrium position.
133768_119114_ans_5a07f9d1368041c9a38e118da626602b.png

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