CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

$$PQR$$ is a triangle in which $$PQ = PR$$ and $$S$$ is any point on the side $$PQ.$$ Through $$S$$, a line is drawn parallel to $$QR$$ and intersecting $$PR$$ at $$T$$. proves that $$PS = PT$$.


Solution


In $$\Delta PQR$$, we have
$$PQ=PR\Rightarrow \angle R=\angle Q$$
Now, $$ST \parallel QR$$.
$$\Rightarrow \angle PST=\angle PQR$$ and $$\angle PTS=\angle PRQ$$     [$$\because $$ Corresponding angles are equal]
$$\Rightarrow \angle PST=\angle Q$$ and $$\angle PTS=\angle R$$
$$\Rightarrow \angle PST=\angle PTS$$

$$\Rightarrow PT=PS$$

1396953_1669869_ans_0bf97dff54584d61838c0e1c985451e8.png

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image