Question

$PQR$ is a triangle right angled at $P$. If $PQ=10cm$ and $PR=24cm$, find $QR$.

Answer 1

It is given that $PQR$ is a right angled triangle.

$PR=24cm,PQ=10cm$

In $△PQR$,

$PR=$ base, $PQ=$ height and $QR=$ hypotenuse

By using Pythagoras Theorem,

$(PR{)}^2+(QP{)}^2=(QR{)}^2$

$(24{)}^2+(10{)}^2=(QR{)}^2$

$\Rightarrow QR=\sqrt{676}=26cm$