CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then ar(RAS) is

Open in App
Solution

In quadrant PLRM, rectangle PQRS is inscribed.
Radius of the circle = 13 cm

A is any point on PQ.
AR and AS are joined, PS = 5 cm
In right PRS, PR2=PS2+SR2(13)2=(5)2+SR2169=25+SR2SR2=16925=144=(12)2SR=12cmArea of rectangle PQRS=PS×SR=5×12=60cm2
Rectangle PQRS and RAS are on the same base SR and between the same parallels
Area RAS=12 Area of rectangle PQRS
=12×60=30cm2


flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A Parallelogram and a Triangle between the Same Parallels_video tackle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon