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Question 4
Prepare a continuous grouped frequency distribution from the following data.

MidPointFrequency5415825133512456


Also, find the size of class intervals.

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Solution

Here, we see that the difference between two mid-points is, 15 - 5 i.e., 10.
It means the width of the class interval is 10.
Let the lower limit of the first class interval be a.
Then, its upper limit = a + 10
Now, mid value of the first class interval = 5
mid value =Lower limit+Upper limit2
5=a+a+1022a+10=10
2a=0a=0
So, the first class interval is 0 - 10.
Now, we prepare a continuous grouped frequency distribution table is given below.

MidpointClass intervalFrequency50104151020825203013353040124540506

The size of the class interval is 10.

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