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Question

Pressure inside two soap bubbles are 1.01 and 1.02 atmospheres. Ratio between their volumes is


  1.  2 : 1

  2. 102 : 101

  3. (102)3 : (101)3

  4. 8 : 1


Solution

The correct option is D

8 : 1


Outside pressure = 1 atm

Pressure inside first bubble = 1.01 atm

Pressure inside second bubble = 1.02 atm

Excess pressure P1 = 1.01 - 1 = 0.01 atm

Excess pressure P2 = 1.02 - 1 0.02 atm

P1rr1Pr1r2=P2P1=0.020.01=21

Since V = 43πr3V1V2=r1r23=213=81

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