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Question

Pressure inside two soap bubbles are 1.01 and 1.02 atmospheres. Ratio between their volumes is

A
102:101
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B
(102)3:(101)3
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C
8:1
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D
2:1
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Solution

The correct option is C 8:1
Outside pressure = 1 atm
Pressure inside first bubble = 1.01 atm
Pressure inside second bubble = 1.02 atm
Excess pressure ΔP1=1.011=0.01 atm
Excess pressure ΔP2=1.021=0.02 atm

ΔP1rr1ΔPr1r2=ΔP2ΔP1=0.020.01=21

Since, V=43πr3V1V2=(r1r2)3=(21)3=81

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