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Byju's Answer
Standard XII
Physics
Excess Pressure in Bubbles
Pressure insi...
Question
Pressure inside two soap bubbles are
1.01
and
1.02
atmospheres. Ratio between their volumes is
A
102
:
101
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B
(
102
)
3
:
(
101
)
3
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C
8
:
1
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D
2
:
1
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Solution
The correct option is
C
8
:
1
Outside pressure =
1
a
t
m
Pressure inside first bubble =
1.01
a
t
m
Pressure inside second bubble =
1.02
a
t
m
Excess pressure
Δ
P
1
=
1.01
−
1
=
0.01
a
t
m
Excess pressure
Δ
P
2
=
1.02
−
1
=
0.02
a
t
m
Δ
P
∝
1
r
⇒
r
∝
1
Δ
P
⇒
r
1
r
2
=
Δ
P
2
Δ
P
1
=
0.02
0.01
=
2
1
Since,
V
=
4
3
π
r
3
∴
V
1
V
2
=
(
r
1
r
2
)
3
=
(
2
1
)
3
=
8
1
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