Question
Primary alkyl halide C4H9Br (X) reacts with alc.KOH to give compound (Y). Compound (Y) reacts with HBr to give compound (Z) which is an isomer of (X). When (X) react with Na metal it gives compound (P).
Hence compound (X), (Y), (Z) and (P) respectively are :
Primary alkyl halide C4H9Br (X) reacts with alc.KOH to give compound (Y). Compound (Y) reacts with HBr to give compound (Z) which is an isomer of (X). When (X) react with Na metal it gives compound (P).
Hence compound (X), (Y), (Z) and (P) respectively are :
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Solution
The correct option is B CH3−CH|CH3−CH2Br; CH3−C|CH3=CH2 ; CH3−Br|C|CH3−CH3 ; C8H18
CH3−CH|CH3−CH2BrXalc.KOH−−−−−→ CH3−C|CH3=CH2YHBr−−−→ CH3−Br|C|CH3−CH3Z CH3−Br|C|CH3−CH3Na−−→ C8H18P
Option A is correct.
CH3−CH|CH3−CH2BrXalc.KOH−−−−−→ CH3−C|CH3=CH2YHBr−−−→ CH3−Br|C|CH3−CH3Z
CH3−Br|C|CH3−CH3Na−−→ C8H18P
Option A is correct.
Option A is correct.
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