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Question 12

Product of 6a27b+5ab and 2ab is
a) 12a3b14ab2+10ab
b) 12a3b14ab2+10a2b2
c) 6a27b+7ab
d) 12a2b7ab2+10ab
 


Solution

b) 12a3b14ab2+10a2b2
Required product = 2ab×(6a27b+5ab)
​​​​​​​This is product of a trinomial by a monomial, so we multiply monomial with each term of the trinomial.
 2ab×(6a27b+5ab)=2ab×6a2+2ab×(7b)+2ab×5ab=12a3b14ab2+10a2b2

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