Proove that interior angle of a regular Pentagon is 3 times the exterior angle of decagon.

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Solution

exterior angle of decagon = 360/10 = 36°
exterior angle of pentagon = 360/5 = 72°
interior angle of pentagon = 180 – 72 = 108°

exterior angle of decagon 36° × 5 = 108
= interior angle of pentagon = 108°

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Proove that interior angle of a regular Pentagon is 3 times the exterior angle of decagon.

exterior angle of decagon = 360/10 = 36° exterior angle of pentagon = 360/5 = 72° interior angle of pentagon = 180 – 72 = 108° exterior angle of decagon 36° × 5 = 108 = interior angle of pentagon = 108°

exterior angle of decagon = 360/10 = 36°
exterior angle of pentagon = 360/5 = 72°
interior angle of pentagon = 180 – 72 = 108°

exterior angle of decagon 36° × 5 = 108
= interior angle of pentagon = 108°