Propene is allowed to react with B $_{2}$ D $_{6}$ and the product is treated with acetic acid. The final product obtained is:

1-deuteriopropane

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2-deuteriopropane

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1-deuteriopropene

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2-deuteriopropene

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Solution

The correct option is D 2-deuteriopropane
this is an example of hydroboration reaction (followed by hydrolysis) in which diborane is isotopically labeled.
A molecule of $H D$ is added across the double bond of propene to form 2-deuteriopropane.
$C H_{2} C H C H_{3} B_{2} D_{6} - ------ \to C H_{3} C O O H C H_{3} - C H D C H_{3}$

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