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Question

Prove by vector method that sin(α+β)=sinαcosβ+cosαsinβ.

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Solution

Let OX and OY be two mutually perpendicular lines intersecting at O.

Let the unit vectors along OX and OY be ^i and ^j

Let OB be a line above axis OX making angle α with the axis OX.

AOB=α+β

Take a point P on OA such that OP=1, PMOX

Take a point Q on OB such that OQ=1,QNOX

OQ=ON+NQ

=(ON)^i+(NQ)^j

=(OQcosα)^i+(OQsinα)^j

=(1cosα)^i+(1sinα)^j

=cosα^i+sinα^j .......(1)

OP=OM+MP

=(OM)^i+(NP)(^j)

=(OPcosβ)^i+(OPsinβ)(^j)

=(1cosβ)^i+(1sinβ)(^j)

=cosβ^isinβ^j ........(2)

OP×OQ=(cosβ^isinβ^j)×(cosα^i+sinα^j)

=cosβcosα(^i×^i)+cosβsinα(^i×^j)sinβcosα(^j×^i)sinβsinα(^j×^j)

=(sinαcosβ+cosαsinβ)^k

Again OP×OQ=1.1sin(α+β)^k

=sin(α+β)^k ........(3)

By equation (2) and (3) we get.
sin(α+β)=sinαcosβ+cosαsinβ.

663942_627402_ans_99b9815986f841b9a860999c08cd318f.png

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