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Question

Prove geometrically that:
cos(A+B)=cosAcosBsinAsinB

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Solution

cos(a+b)=ACBC=ACFD
=cos(a)cos(b)sin(a)sin(b)
sin(a+b)=BF+FE=CA+FE
=sin(a)cos(b)+cos(a)sin(b)

1377787_1150390_ans_fd65b0019c414f45a2b2657ee5e59480.png

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