Question

# Prove that an ideal inductor does not dissipate power in an a.c. circuit.

Solution

## The instantaneous EMF is given by E=$$E_o$$Sin$$\omega$$tthe instantaneous current in the inductor is given by I=$$I_o$$cos$$\omega$$tthe instantaneous power in the inductor is given by P=EI=$$E_o$$$$I_o$$$$cos\omega$$tsin$$\omega$$t= $$\dfrac{E_oI_osin2\omega t}{2}$$the average power over the complete cycle $$Pav$$=$$\dfrac{E_oI_osin2\omega t}{2}$$=0hence,an ideal inductor does not dissipate powerPhysics

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