CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Prove that an ideal inductor does not dissipate power in an a.c. circuit.


Solution

The instantaneous EMF is given by E=$$E_o$$Sin$$\omega$$t
the instantaneous current in the inductor is given by I=$$I_o$$cos$$\omega$$t
the instantaneous power in the inductor is given by P=EI
=$$E_o$$$$I_o$$$$cos\omega$$tsin$$\omega$$t
= $$\dfrac{E_oI_osin2\omega t}{2}$$
the average power over the complete cycle $$Pav$$=$$\dfrac{E_oI_osin2\omega t}{2}$$=0
hence,an ideal inductor does not dissipate power

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image